### Shortcuts and Formulas For Time and Work Problems/Tricks and Tips to solve Quickly :

Hey, Aspirants this time we are going to solve time and work problems with **shortcut tricks**.Time and Work is an important topic in all competitive exams. In this article I decided to share **shortcut techniques related to Time and Distance problems** that can be used in competitive exams. **Problems on time and work** which appear in CAT, SSC CGL, SSC CHSL, IBPS, and other competitive exams are quite advanced and complicated – But they can be solved easily if you know the basic formulas, shortcuts and tricks. Now, we are going to **solve work and time problem with Shortcuts and Formulas. **If you learn these tricks you can solve these question in seconds.

This section will provide you Shortcuts and Formulas[Tricks and Tips] to solve problems on time and work.These Shortcuts and Formulas are similar to ratio and proportion shortcuts or time and distance shortcuts. So, all you have to do is be thorough with the basics and practice as many questions as you can.

### Basic Concepts Of Time and Work :

Simply don’t by heart Shortcuts and Tricks.You should actually take time and learn some basic concepts regarding Time and Work problems. You have to learns relations between Time and Work, how one arrives at these shortcuts, try it out yourself, then solve as many problems you can.With this you will get an idea on where to use these shortcuts.Then you solve questions later on. Most of the questions on Time and Work can be solved if you know the basic correlation between Time, Work and Man-hours.

- More work means more time required to do work.
- More men can do more work.
- More men can do more work in less time.
**M**men can do a piece of work in**T**hours, then Total effort or work =**MT**man hours.- Rate of work * Time = Work Done.
- If A can do a piece of work in
**D**days, then A‘s 1 day’s work =**1/D.**

Part of work done by**A**for**t**days =**tD.** - If A‘s 1 day’s work =
**1D**, then A can finish the work in**D**days. -
**MDHW=Constant**

Where,**M**= Number of men

**D**= Number of days

**H**= Number of hours per day

**W**= Amount of work - If
**M1**men can do**W1**work in**D1**days working**H1**hours per day and**M2**men can do**W2**work in**D2**days working**H2**hours per day, then**M1*D1*H1*W1=M2*D2*H2*W2** - If A is
**x**times as good a workman as B, then:- Ratio of work done by A and B =
**x:1** - Ratio of times taken by A and B to finish a work =
**1:x**i.e; A will take**(1/x)th**of the time taken by B to do the same work.

- Ratio of work done by A and B =

**Analogy between problems on Time and Work and Distance,Time and Speed:**

- Time to travel Distance is equivalent to Time to do Work.
- Speed is equivalent to rate at which work is done
- Distance travelled is equivalent to work done.

## Shortcuts and Formulas for Time and Work Problems:

- A and B can do a piece of work in
**‘a‘**days and**‘b‘**days respectively, then working together:- They will complete the work in
**aba+baba+b**days - In one day, they will finish
**(a+bab)th**part of work.

- They will complete the work in
- If AA can do a piece of work in
**aa**days, BB can do in**bb**days and CC can do in**cc**days then,A, B and C together can finish the same work in**abcab+bc+ca**days. - If AA can do a work in
**xx**days and AA and BB together can do the same work in**yy**days then,Number of days required to complete the work if B works alone= days. -
Number of days required to complete the work if B works alone=
**xyx-y**days - If AA and BB together can do a piece of work in
**xx**days, BB and CC together can do it in**yy**days and CC and AA together can do it in**zz**days, then number of days required to do the same work:- If A, B, and C working together =
**2xyzxy+yz+zx2xyzxy+yz+zx** - If A working alone =
**2xyzxy+yz−zx2xyzxy+yz-zx** - If B working alone =
**2xyz−xy+yz+zx2xyz-xy+yz+zx** - If C working alone =
**2xyzxy−yz+zx2xyzxy-yz+zx**

- If A, B, and C working together =
- If AA and BB can together complete a job in
**xx**days.

If AA alone does the work and takes**aa**days more than AA and BB working together.

If BB alone does the work and takes**bb**days more than AA and BB working together.Then,x=ab−−√ daysx=ab days - If
**m1m1**men or**b1b1**boys can complete a work in**DD**days, then**m2m2**men and**b2b2**boys can complete the same work in**Dm1b1m2b1+m1b2Dm1b1m2b1+m1b2**days. - If
**mm**men or**ww**women or**bb**boys can do work in**DD**days, then 1 man, 1 woman and 1 boy together can together do the same work in**Dmwbmw+wb+bmDmwbmw+wb+bm**days - If the number of men to do a job is changed in the ratio
**a:b,**then the time required to do the work will be changed in the inverse ratio. ie;**b:a.** - If people work for same number of days, ratio in which the total money earned has to be shared is the ratio of work done per day by each one of them.

AA, BB, CC can do a piece of work in xx, yy, zz days respectively. The ratio in which the amount earned should be shared is**1x:1y:1z=yz:zx:xy** - If people work for different number of days, ratio in which the total money earned has to be shared is the ratio of work done by each one of them.