Shortcuts and Formulas For Time and Work Problems/Tricks and Tips to solve Quickly

Shortcuts and Formulas For Time and Work Problems/Tricks and Tips to solve Quickly :

Hey, Aspirants this time we are going to solve time and work problems with shortcut tricks.Time and Work is an important topic in all competitive exams. In this article I decided to share shortcut techniques related to Time and Distance problems that can be used in competitive exams. Problems on time and work which appear in CAT, SSC CGL, SSC CHSL, IBPS, and other competitive exams are quite advanced and complicated – But they can be solved easily if you know the basic formulas, shortcuts and tricks. Now, we are going to solve work and time problem with Shortcuts and Formulas. If you learn these tricks you can solve these question in seconds.

This section will provide you Shortcuts and Formulas[Tricks and Tips] to solve problems on time and work.These Shortcuts and Formulas are similar to ratio and proportion shortcuts or time and distance shortcuts. So, all you have to do is be thorough with the basics and practice as many questions as you can.

Basic Concepts Of Time and Work :

Simply don’t by heart Shortcuts and Tricks.You should actually take time and learn some basic concepts regarding Time and Work problems. You have to learns relations between Time and Work, how one arrives at these shortcuts, try it out yourself, then solve as many problems you can.With this you will get an idea on where to  use these shortcuts.Then you solve questions later on. Most of the questions on Time and Work can be solved if you know the basic correlation between Time, Work and Man-hours.

  1. More work means more time required to do work.
  2. More men can do more work.
  3. More men can do more work in less time.
  4. M men can do a piece of work in T hours, then Total effort or work =MT man hours.
  5. Rate of work * Time = Work Done.
  6. If A can do a piece of work in D days, then A‘s 1 day’s work = 1/D.
    Part of work done by A for t days = tD.
  7. If A‘s 1 day’s work = 1D, then A can finish the work in D days.
  8. MDHW=Constant
    Where,

    M = Number of men
    D = Number of days
    H = Number of hours per day
    W = Amount of work
  9. If M1 men can do W1 work in D1 days working H1 hours per day and M2 men can do W2 work in D2 days working H2 hours per day, then
    M1*D1*H1*W1=M2*D2*H2*W2
  10. If A is x times as good a workman as B, then:
    1. Ratio of work done by A and B = x:1
    2. Ratio of times taken by and B to finish a work = 1:x i.e; A will take (1/x)th of the time taken by B to do the same work.

Analogy between problems on Time and Work and Distance,Time and Speed:

  1. Time to travel Distance is equivalent to Time to do Work.
  2. Speed is equivalent to rate at which work is done
  3. Distance travelled is equivalent to work done.

Shortcuts and Formulas for Time and Work Problems:

  • A and B can do a piece of work in a days and b days respectively, then working together:
    1. They will complete the work in aba+baba+b days
    2. In one day, they will finish (a+bab)th part of work.
  • If AA can do a piece of work in aa days, BB can do in bb days and CC can do in cc days then,
    A, B and C together can finish the same work in abcab+bc+ca days.
  • If AA can do a work in xx days and AA and BB together can do the same work in yy days then,
    Number of days required to complete the work if B works alone= days. 
  • Number of days required to complete the work if B works alone=xyx-y days
  • If AA and BB together can do a piece of work in xx days, BB and CC together can do it in yy days and CC and AA together can do it in zz days, then number of days required to do the same work:
    1. If A, B, and C working together = 2xyzxy+yz+zx2xyzxy+yz+zx
    2. If A working alone = 2xyzxy+yzzx2xyzxy+yz-zx
    3. If B working alone = 2xyzxy+yz+zx2xyz-xy+yz+zx
    4. If C working alone = 2xyzxyyz+zx2xyzxy-yz+zx
  • If AA and BB can together complete a job in xx days.
    If AA alone does the work and takes aa days more than AA and BB working together.
    If BB alone does the work and takes bb days more than AA and BB working together.

    Then,x=ab−−√ daysx=ab days
  • If m1m1 men or b1b1 boys can complete a work in DD days, then m2m2 men and b2b2 boys can complete the same work in Dm1b1m2b1+m1b2Dm1b1m2b1+m1b2 days.
  • If mm men or ww women or bb boys can do work in DD days, then 1 man, 1 woman and 1 boy together can together do the same work in Dmwbmw+wb+bmDmwbmw+wb+bm days
  • If the number of men to do a job is changed in the ratio a:b, then the time required to do the work will be changed in the inverse ratio. ie; b:a.
  • If people work for same number of days, ratio in which the total money earned has to be shared is the ratio of work done per day by each one of them.
    AA, BB, CC can do a piece of work in xx, yy, zz days respectively. The ratio in which the amount earned should be shared is 1x:1y:1z=yz:zx:xy
  • If people work for different number of days, ratio in which the total money earned has to be shared is the ratio of work done by each one of them.

 

 

 

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